z^2-3*(1+i)*z+5i=0

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Solution for z^2-3*(1+i)*z+5i=0 equation:


Simplifying
z2 + -3(1 + i) * z + 5i = 0

Reorder the terms for easier multiplication:
z2 + -3z(1 + i) + 5i = 0
z2 + (1 * -3z + i * -3z) + 5i = 0

Reorder the terms:
z2 + (-3iz + -3z) + 5i = 0
z2 + (-3iz + -3z) + 5i = 0

Reorder the terms:
5i + -3iz + -3z + z2 = 0

Solving
5i + -3iz + -3z + z2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '3z' to each side of the equation.
5i + -3iz + -3z + 3z + z2 = 0 + 3z

Combine like terms: -3z + 3z = 0
5i + -3iz + 0 + z2 = 0 + 3z
5i + -3iz + z2 = 0 + 3z
Remove the zero:
5i + -3iz + z2 = 3z

Add '-1z2' to each side of the equation.
5i + -3iz + z2 + -1z2 = 3z + -1z2

Combine like terms: z2 + -1z2 = 0
5i + -3iz + 0 = 3z + -1z2
5i + -3iz = 3z + -1z2

Reorder the terms:
5i + -3iz + -3z + z2 = 3z + -3z + -1z2 + z2

Combine like terms: 3z + -3z = 0
5i + -3iz + -3z + z2 = 0 + -1z2 + z2
5i + -3iz + -3z + z2 = -1z2 + z2

Combine like terms: -1z2 + z2 = 0
5i + -3iz + -3z + z2 = 0

The solution to this equation could not be determined.

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